Distance from Dimitrovgrad to Walnut Creek
Distance from Dimitrovgrad to Walnut Creek is 9,766 kilometers. This air travel distance is equal to 6,068 miles.
The air travel (bird fly) shortest distance between Dimitrovgrad and Walnut Creek is 9,766 km= 6,068 miles.
If you travel with an airplane (which has average speed of 560 miles) from Dimitrovgrad to Walnut Creek, It takes 10.84 hours to arrive.
Dimitrovgrad
Dimitrovgrad is located in Russia.
GPS Coordinates (DMS) | 54° 12´ 49.8960'' N 49° 37´ 6.1680'' E |
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Latitude | 54.21386 |
Longitude | 49.61838 |
Altitude | 56 m |
Country | Russia |
Dimitrovgrad Distances to Cities
Dimitrovgrad | Distance |
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Distance from Dimitrovgrad to Opportunity | 8,647 km |
Distance from Dimitrovgrad to Lynn Haven | 9,712 km |
Distance from Dimitrovgrad to Fond Du Lac | 8,441 km |
Distance from Dimitrovgrad to Irvine | 10,193 km |
Distance from Dimitrovgrad to Wilkes Barre | 8,226 km |
Walnut Creek
Walnut Creek is located in United States.
GPS Coordinates | 37° 54´ 22.7160'' N 122° 3´ 53.8560'' W |
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Latitude | 37.90631 |
Longitude | -122.06496 |
Altitude | 54 m |
Country | United States |