Distance from Deerfield Beach to Jefferson City
Distance from Deerfield Beach to Jefferson City is 1,768 kilometers. This air travel distance is equal to 1,099 miles.
The air travel (bird fly) shortest distance between Deerfield Beach and Jefferson City is 1,768 km= 1,099 miles.
If you travel with an airplane (which has average speed of 560 miles) from Deerfield Beach to Jefferson City, It takes 1.96 hours to arrive.
Deerfield Beach
Deerfield Beach is located in United States.
| GPS Coordinates (DMS) | 26° 19´ 6.2760'' N 80° 5´ 59.1720'' W |
|---|---|
| Latitude | 26.31841 |
| Longitude | -80.09977 |
| Altitude | 9 m |
| Country | United States |
Deerfield Beach Distances to Cities
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |