Distance from to

Distance from Connecticut to San Angelo

Distance from Connecticut to San Angelo is 2,680 kilometers. This air travel distance is equal to 1,665 miles.

The air travel (bird fly) shortest distance between Connecticut and San Angelo is 2,680 km= 1,665 miles.

If you travel with an airplane (which has average speed of 560 miles) from Connecticut to San Angelo, It takes 2.97 hours to arrive.

Connecticut

Connecticut is located in United States.

GPS Coordinates (DMS)41° 36´ 11.5920'' N
73° 5´ 15.9000'' W
Latitude41.60322
Longitude-73.08775
Altitude207 m
CountryUnited States

Connecticut Distances to Cities

ConnecticutDistance
Distance from Connecticut to New York125 km
Distance from Connecticut to New Jersey204 km
Distance from Connecticut to California3,990 km
Distance from Connecticut to Boston188 km
Distance from Connecticut to Pennsylvania346 km

San Angelo

San Angelo is located in United States.

GPS Coordinates31° 27´ 49.5720'' N
100° 26´ 13.3440'' W
Latitude31.46377
Longitude-100.43704
Altitude564 m
CountryUnited States

San Angelo Distances to Cities

San AngeloDistance
Distance from San Angelo to Eagle1,948 km
Distance from San Angelo to Moscow2,210 km
Distance from San Angelo to West Odessa200 km
Distance from San Angelo to Albany Or2,455 km
Distance from San Angelo to Twin Falls1,749 km