Distance from Connecticut to San Angelo
Distance from Connecticut to San Angelo is 2,680 kilometers. This air travel distance is equal to 1,665 miles.
The air travel (bird fly) shortest distance between Connecticut and San Angelo is 2,680 km= 1,665 miles.
If you travel with an airplane (which has average speed of 560 miles) from Connecticut to San Angelo, It takes 2.97 hours to arrive.
Connecticut
Connecticut is located in United States.
| GPS Coordinates (DMS) | 41° 36´ 11.5920'' N 73° 5´ 15.9000'' W |
|---|---|
| Latitude | 41.60322 |
| Longitude | -73.08775 |
| Altitude | 207 m |
| Country | United States |
Connecticut Distances to Cities
| Connecticut | Distance |
|---|---|
| Distance from Connecticut to New York | 125 km |
| Distance from Connecticut to New Jersey | 204 km |
| Distance from Connecticut to Boston | 188 km |
| Distance from Connecticut to California | 3,990 km |
| Distance from Connecticut to Pennsylvania | 346 km |
San Angelo
San Angelo is located in United States.
| GPS Coordinates | 31° 27´ 49.5720'' N 100° 26´ 13.3440'' W |
|---|---|
| Latitude | 31.46377 |
| Longitude | -100.43704 |
| Altitude | 564 m |
| Country | United States |
San Angelo Distances to Cities
| San Angelo | Distance |
|---|---|
| Distance from San Angelo to Eagle | 1,948 km |
| Distance from San Angelo to West Odessa | 200 km |
| Distance from San Angelo to Moscow | 2,210 km |
| Distance from San Angelo to Twin Falls | 1,749 km |
| Distance from San Angelo to Albany Or | 2,455 km |