Distance from Clayton to Jefferson City
Distance from Clayton to Jefferson City is 161 kilometers. This air travel distance is equal to 100 miles.
The air travel (bird fly) shortest distance between Clayton and Jefferson City is 161 km= 100 miles.
If you travel with an airplane (which has average speed of 560 miles) from Clayton to Jefferson City, It takes 0.18 hours to arrive.
Clayton
Clayton is located in United States.
| GPS Coordinates (DMS) | 38° 38´ 33.1800'' N 90° 19´ 25.4280'' W |
|---|---|
| Latitude | 38.64255 |
| Longitude | -90.32373 |
| Altitude | 175 m |
| Country | United States |
Clayton Distances to Cities
| Clayton | Distance |
|---|---|
| Distance from Clayton Mo to Charleston Wv | 759 km |
| Distance from Clayton Mo to Merced | 2,642 km |
| Distance from Clayton Mo to Flagstaff | 1,934 km |
| Distance from Clayton Mo to Des Moines Ia | 432 km |
| Distance from Clayton Mo to San Jose | 2,763 km |
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |