Distance from to

Distance from Clarksville to San Angelo

Distance from Clarksville to San Angelo is 1,538 kilometers. This air travel distance is equal to 956 miles.

The air travel (bird fly) shortest distance between Clarksville and San Angelo is 1,538 km= 956 miles.

If you travel with an airplane (which has average speed of 560 miles) from Clarksville to San Angelo, It takes 1.71 hours to arrive.

Clarksville

Clarksville is located in United States.

GPS Coordinates (DMS)38° 17´ 48.2640'' N
85° 45´ 35.8560'' W
Latitude38.29674
Longitude-85.75996
Altitude140 m
CountryUnited States

Clarksville Distances to Cities

ClarksvilleDistance
Distance from Clarksville In to Bethesda757 km
Distance from Clarksville In to Elkridge793 km
Distance from Clarksville In to Nashville253 km
Distance from Clarksville In to Glen Burnie800 km
Distance from Clarksville In to Seven Oaks628 km

San Angelo

San Angelo is located in United States.

GPS Coordinates31° 27´ 49.5720'' N
100° 26´ 13.3440'' W
Latitude31.46377
Longitude-100.43704
Altitude564 m
CountryUnited States

San Angelo Distances to Cities

San AngeloDistance
Distance from San Angelo to Eagle1,948 km
Distance from San Angelo to Moscow2,210 km
Distance from San Angelo to West Odessa200 km
Distance from San Angelo to Albany Or2,455 km
Distance from San Angelo to Twin Falls1,749 km