Distance from Austin to Seymour
Distance from Austin to Seymour is 2,535 kilometers. This air travel distance is equal to 1,575 miles.
The air travel (bird fly) shortest distance between Austin and Seymour is 2,535 km= 1,575 miles.
If you travel with an airplane (which has average speed of 560 miles) from Austin to Seymour, It takes 2.81 hours to arrive.
Austin
Austin is located in United States.
| GPS Coordinates (DMS) | 30° 16´ 1.7400'' N 97° 44´ 35.0160'' W |
|---|---|
| Latitude | 30.26715 |
| Longitude | -97.74306 |
| Altitude | 165 m |
| Country | United States |
Austin Distances to Cities
| Austin | Distance |
|---|---|
| Distance from Austin Tx to San Francisco | 2,418 km |
| Distance from Austin Tx to Dallas | 293 km |
| Distance from Austin Tx to Santa Fe | 973 km |
| Distance from Austin Tx to Honolulu | 6,043 km |
| Distance from Austin Tx to Boston | 2,729 km |
Seymour
Seymour is located in United States.
| GPS Coordinates | 41° 23´ 48.3360'' N 73° 4´ 33.3840'' W |
|---|---|
| Latitude | 41.39676 |
| Longitude | -73.07594 |
| Altitude | 30 m |
| Country | United States |
Seymour Distances to Cities
| Seymour | Distance |
|---|---|
| Distance from Seymour Ct to Torrance | 4,036 km |
| Distance from Seymour Ct to Orange Ca | 3,998 km |
| Distance from Seymour Ct to Cambridge | 196 km |
| Distance from Seymour Ct to Albany Ca | 4,186 km |
| Distance from Seymour Ct to Bedford Nh | 215 km |