Distance from Arauco to Dracut
Distance from Arauco to Dracut is 8,852 kilometers. This air travel distance is equal to 5,500 miles.
The air travel (bird fly) shortest distance between Arauco and Dracut is 8,852 km= 5,500 miles.
If you travel with an airplane (which has average speed of 560 miles) from Arauco to Dracut, It takes 9.82 hours to arrive.
Arauco
Arauco is located in Chile.
| GPS Coordinates (DMS) | 37° 14´ 46.6800'' S 73° 19´ 3.0720'' W |
|---|---|
| Latitude | -37.24630 |
| Longitude | -73.31752 |
| Altitude | 13 m |
| Country | Chile |
Arauco Distances to Cities
| Arauco | Distance |
|---|---|
| Distance from Arauco to Dracut | 8,852 km |
| Distance from Arauco to Avenel | 8,618 km |
| Distance from Arauco to League City | 7,731 km |
| Distance from Arauco to Reston | 8,449 km |
| Distance from Arauco to Redwood City | 9,683 km |
Dracut
Dracut is located in United States.
| GPS Coordinates | 42° 40´ 13.3320'' N 71° 18´ 7.2360'' W |
|---|---|
| Latitude | 42.67037 |
| Longitude | -71.30201 |
| Altitude | 51 m |
| Country | United States |