Distance from Arauca to Viterbo
Distance from Arauca to Viterbo is 608 kilometers. This air travel distance is equal to 378 miles.
The air travel (bird fly) shortest distance between Arauca and Viterbo is 608 km= 378 miles.
If you travel with an airplane (which has average speed of 560 miles) from Arauca to Viterbo, It takes 0.67 hours to arrive.
Arauca
Arauca is located in Colombia.
| GPS Coordinates (DMS) | 7° 4´ 45.7320'' N 70° 45´ 30.1680'' W |
|---|---|
| Latitude | 7.07937 |
| Longitude | -70.75838 |
| Altitude | 129 m |
| Country | Colombia |
Arauca Distances to Cities
| Arauca | Distance |
|---|---|
| Distance from Arauca to Tame | 127 km |
| Distance from Arauca to Bogota | 458 km |
| Distance from Arauca to Lorica | 606 km |
| Distance from Arauca to Antioquia | 506 km |
| Distance from Arauca to Barranquilla | 617 km |
Viterbo
Viterbo is located in Colombia.
| GPS Coordinates | 5° 3´ 44.7120'' N 75° 52´ 17.7240'' W |
|---|---|
| Latitude | 5.06242 |
| Longitude | -75.87159 |
| Altitude | 976 m |
| Country | Colombia |
Viterbo Distances to Cities
| Viterbo | Distance |
|---|---|
| Distance from Viterbo to Chia | 202 km |
| Distance from Viterbo to El Cerrito | 160 km |
| Distance from Viterbo to Bogota | 205 km |
| Distance from Viterbo to Granada | 293 km |
| Distance from Viterbo to Maicao | 805 km |