Distance from Arauca to Sibate
Distance from Arauca to Sibaté is 481 kilometers. This air travel distance is equal to 299 miles.
The air travel (bird fly) shortest distance between Arauca and Sibaté is 481 km= 299 miles.
If you travel with an airplane (which has average speed of 560 miles) from Arauca to Sibate, It takes 0.53 hours to arrive.
Arauca
Arauca is located in Colombia.
GPS Coordinates (DMS) | 7° 4´ 45.7320'' N 70° 45´ 30.1680'' W |
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Latitude | 7.07937 |
Longitude | -70.75838 |
Altitude | 129 m |
Country | Colombia |
Arauca Distances to Cities
Arauca | Distance |
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Distance from Arauca to Tame | 127 km |
Distance from Arauca to Bogota | 458 km |
Distance from Arauca to Lorica | 606 km |
Distance from Arauca to Antioquia | 506 km |
Distance from Arauca to Barranquilla | 617 km |
Sibate
Sibate is located in Colombia.
GPS Coordinates | 4° 29´ 3.3000'' N 74° 14´ 41.9640'' W |
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Latitude | 4.48425 |
Longitude | -74.24499 |
Altitude | 2767 m |
Country | Colombia |
Sibaté Distances to Cities
Sibaté | Distance |
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Distance from Sibate to Sevilla | 189 km |
Distance from Sibate to Granada | 120 km |
Distance from Sibate to San Martin | 106 km |
Distance from Sibate to Malaga | 297 km |
Distance from Sibate to Bogota | 23 km |