Distance from Arauca to Segovia
Distance from Arauca to Segovia is 435 kilometers. This air travel distance is equal to 270 miles.
The air travel (bird fly) shortest distance between Arauca and Segovia is 435 km= 270 miles.
If you travel with an airplane (which has average speed of 560 miles) from Arauca to Segovia, It takes 0.48 hours to arrive.
Arauca
Arauca is located in Colombia.
| GPS Coordinates (DMS) | 7° 4´ 45.7320'' N 70° 45´ 30.1680'' W |
|---|---|
| Latitude | 7.07937 |
| Longitude | -70.75838 |
| Altitude | 129 m |
| Country | Colombia |
Arauca Distances to Cities
| Arauca | Distance |
|---|---|
| Distance from Arauca to Tame | 127 km |
| Distance from Arauca to Bogota | 458 km |
| Distance from Arauca to Lorica | 606 km |
| Distance from Arauca to Antioquia | 506 km |
| Distance from Arauca to Barranquilla | 617 km |
Segovia
Segovia is located in Colombia.
| GPS Coordinates | 7° 4´ 47.7480'' N 74° 41´ 56.0400'' W |
|---|---|
| Latitude | 7.07993 |
| Longitude | -74.69890 |
| Altitude | 680 m |
| Country | Colombia |
Segovia Distances to Cities
| Segovia | Distance |
|---|---|
| Distance from Segovia to Medellin | 132 km |
| Distance from Segovia to Malaga | 221 km |
| Distance from Segovia to Madrid | 264 km |
| Distance from Segovia to Andalucia | 360 km |
| Distance from Segovia to Lorica | 268 km |