Distance from Arauca to San Benito Abad
Distance from Arauca to San Benito Abad is 513 kilometers. This air travel distance is equal to 319 miles.
The air travel (bird fly) shortest distance between Arauca and San Benito Abad is 513 km= 319 miles.
If you travel with an airplane (which has average speed of 560 miles) from Arauca to San Benito Abad, It takes 0.57 hours to arrive.
Arauca
Arauca is located in Colombia.
| GPS Coordinates (DMS) | 7° 4´ 45.7320'' N 70° 45´ 30.1680'' W |
|---|---|
| Latitude | 7.07937 |
| Longitude | -70.75838 |
| Altitude | 129 m |
| Country | Colombia |
Arauca Distances to Cities
| Arauca | Distance |
|---|---|
| Distance from Arauca to Tame | 127 km |
| Distance from Arauca to Bogota | 458 km |
| Distance from Arauca to Lorica | 606 km |
| Distance from Arauca to Antioquia | 506 km |
| Distance from Arauca to Barranquilla | 617 km |
San Benito Abad
San Benito Abad is located in Colombia.
| GPS Coordinates | 8° 55´ 44.4360'' N 75° 1´ 37.5240'' W |
|---|---|
| Latitude | 8.92901 |
| Longitude | -75.02709 |
| Altitude | 23 m |
| Country | Colombia |