Distance from Arauca to Palmar de Varela
Distance from Arauca to Palmar de Varela is 598 kilometers. This air travel distance is equal to 372 miles.
The air travel (bird fly) shortest distance between Arauca and Palmar de Varela is 598 km= 372 miles.
If you travel with an airplane (which has average speed of 560 miles) from Arauca to Palmar de Varela, It takes 0.66 hours to arrive.
Arauca
Arauca is located in Colombia.
| GPS Coordinates (DMS) | 7° 4´ 45.7320'' N 70° 45´ 30.1680'' W |
|---|---|
| Latitude | 7.07937 |
| Longitude | -70.75838 |
| Altitude | 129 m |
| Country | Colombia |
Arauca Distances to Cities
| Arauca | Distance |
|---|---|
| Distance from Arauca to Tame | 127 km |
| Distance from Arauca to Bogota | 458 km |
| Distance from Arauca to Lorica | 606 km |
| Distance from Arauca to Antioquia | 506 km |
| Distance from Arauca to Barranquilla | 617 km |
Palmar de Varela
Palmar de Varela is located in Colombia.
| GPS Coordinates | 10° 44´ 25.9800'' N 74° 45´ 15.9480'' W |
|---|---|
| Latitude | 10.74055 |
| Longitude | -74.75443 |
| Altitude | 12 m |
| Country | Colombia |