Distance from Arauca to Cienaga de Oro
Distance from Arauca to Ciénaga de Oro is 572 kilometers. This air travel distance is equal to 355 miles.
The air travel (bird fly) shortest distance between Arauca and Ciénaga de Oro is 572 km= 355 miles.
If you travel with an airplane (which has average speed of 560 miles) from Arauca to Cienaga de Oro, It takes 0.63 hours to arrive.
Arauca
Arauca is located in Colombia.
| GPS Coordinates (DMS) | 7° 4´ 45.7320'' N 70° 45´ 30.1680'' W |
|---|---|
| Latitude | 7.07937 |
| Longitude | -70.75838 |
| Altitude | 129 m |
| Country | Colombia |
Arauca Distances to Cities
| Arauca | Distance |
|---|---|
| Distance from Arauca to Tame | 127 km |
| Distance from Arauca to Bogota | 458 km |
| Distance from Arauca to Lorica | 606 km |
| Distance from Arauca to Antioquia | 506 km |
| Distance from Arauca to Barranquilla | 617 km |
Cienaga de Oro
Cienaga de Oro is located in Colombia.
| GPS Coordinates | 8° 52´ 27.9480'' N 75° 37´ 13.0080'' W |
|---|---|
| Latitude | 8.87443 |
| Longitude | -75.62028 |
| Altitude | 16 m |
| Country | Colombia |