Distance from Aleksandrovskoye to Vostochnoe Degunino
Distance from Aleksandrovskoye to Vostochnoe Degunino is 1,300 kilometers. This air travel distance is equal to 808 miles.
The air travel (bird fly) shortest distance between Aleksandrovskoye and Vostochnoe Degunino is 1,300 km= 808 miles.
If you travel with an airplane (which has average speed of 560 miles) from Aleksandrovskoye to Vostochnoe Degunino, It takes 1.44 hours to arrive.
Aleksandrovskoye
Aleksandrovskoye is located in Russia.
| GPS Coordinates (DMS) | 44° 42´ 51.0120'' N 43° 0´ 2.9880'' E |
|---|---|
| Latitude | 44.71417 |
| Longitude | 43.00083 |
| Altitude | 295 m |
| Country | Russia |
Aleksandrovskoye Distances to Cities
| Aleksandrovskoye | Distance |
|---|---|
| Distance from Aleksandrovskoye to Dagomys | 291 km |
| Distance from Aleksandrovskoye to Kyzyl | 3,819 km |
| Distance from Aleksandrovskoye to Kyakhta | 4,671 km |
| Distance from Aleksandrovskoye to Krasnoyarsk | 3,671 km |
| Distance from Aleksandrovskoye to Prokop Yevsk | 3,280 km |
Vostochnoe Degunino
Vostochnoe Degunino is located in Russia.
| GPS Coordinates | 55° 52´ 48.3600'' N 37° 33´ 27.2880'' E |
|---|---|
| Latitude | 55.88010 |
| Longitude | 37.55758 |
| Altitude | 174 m |
| Country | Russia |